102 lines
3.9 KiB
HTML
102 lines
3.9 KiB
HTML
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<!DOCTYPE html PUBLIC "-//w3c//dtd html 4.0 transitional//en">
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<html>
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<head>
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<meta http-equiv="Content-Type" content="text/html;
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charset=windows-1252">
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<meta name="GENERATOR" content="Mozilla/4.7 [en] (X11; U; OSF1 V4.0
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alpha) [Netscape]">
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<meta name="Author" content="C. L. Davis">
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<title>Electricity - Charged Particle Motion in an Electric Field -
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Physics 299</title>
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</head>
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<body style="color: rgb(0, 0, 0); background-color: rgb(255, 255,
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255);" link="#0000ee" alink="#ff0000" vlink="#551a8b">
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<center>
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<h1> <img src="ULPhys1.gif" height="50" align="texttop"
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width="189"></h1>
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</center>
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<center>
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<h1>Charged Particle Motion in an Electric Field <br>
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</h1>
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</center>
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<center><img src="celticbar.gif" height="22" width="576"><br>
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<br>
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<font color="#ff0000"><i>"</i></font><font color="#ff0000"><i>
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<meta http-equiv="content-type" content="text/html;
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charset=windows-1252">
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The hardest thing in the world to understand is the income tax"</i></font><br>
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Albert Einstein<br>
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</center>
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<img src="netbar.gif" height="40" align="middle" width="100%"> <br>
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<ul>
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</ul>
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<ul>
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<li>Having determined the electric field we now want to determine
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the behaviour of a point charge, q<sub>0</sub>, placed in this
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field.</li>
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</ul>
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<ul>
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<li>The force on the charge is given by <b>F</b> = q<sub>0</sub><b>E</b>.
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But Newton's second law tells us that <b>F</b> = m<b>a</b>, so
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that the acceleration of the particle can be written, <b>a</b>
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= (q<sub>0</sub>/m)<b>E</b>.</li>
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</ul>
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<ul>
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<li>Once we have an expression for the acceleration it is usually
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possible to determine the trajectory of the particle, although
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in the general case this will involve solving differential
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equations. However, when <b>E</b> is constant the
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acceleration is constant which allows us to use the kinematic
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equations describing motion under constant acceleration from the
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beginning of the first semester of this course (Physics
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298). Important equations in Physics should never be
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forgotten <img alt="sadface" src="sadface.jpg" height="24"
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width="24">. <br>
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</li>
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</ul>
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<ul>
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<li>In two dimensions, with <b>E</b> constant in one direction
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and zero in the other, charged particle motion can be treated in
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the same way as projectile motion of a particle under the
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influence of a (constant) gravitational field.</li>
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</ul>
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<div align="center"><img alt="charged particle motion"
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src="elec_charged_particle_motion.jpg" height="172" width="292"><br>
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</div>
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<ul>
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</ul>
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<ul>
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</ul>
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<div align="center"> </div>
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<div style="text-align: left;"><img src="netbar.gif" height="40"
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width="100%"> </div>
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<center><span style="font-size: 12pt; font-family: "Times New
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Roman";"><span style="color: rgb(255, 0, 0); font-style:
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italic;"></span></span><span style="font-size: 12pt;
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font-family: "Times New Roman";"><span style="color:
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rgb(255, 0, 0); font-style: italic;">
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<meta http-equiv="content-type" content="text/html;
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charset=windows-1252">
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</span></span><br>
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<i><font color="#ff0000">What do you get if you have Avogadro's
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number of donkeys?
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Answer: molasses (a mole of asses)</font></i><br>
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<br>
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<img src="celticbar.gif" height="22" width="576"> <br>
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<p><i>Dr. C. L. Davis</i> <br>
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<i>Physics Department</i> <br>
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<i>University of Louisville</i> <br>
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<i>email</i>: <a href="mailto:c.l.davis@louisville.edu">c.l.davis@louisville.edu</a>
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<br>
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</p>
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<p><img src="header-index.gif" height="51" width="92"> </p>
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</center>
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<p><br>
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</p>
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</body>
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</html>
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